What is the equation of a vertical transverse hyperbola in pre-calculus?
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The equation of a vertical transverse hyperbola is \( \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 \), where \((h, k)\) is the center, \(a\) is the distance from the center to each vertex along the vertical axis, and \(b\) relates to the conjugate axis length.
How do you find the vertices of a vertical transverse hyperbola?
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For a vertical transverse hyperbola with center \((h, k)\), the vertices are located at \((h, k \pm a)\), where \(a\) is the distance from the center to each vertex along the vertical axis.
What is the difference between a vertical and horizontal transverse hyperbola?
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In a vertical transverse hyperbola, the transverse axis is vertical, so the \(y\)-term comes first and is positive in the standard equation \( \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 \). In a horizontal transverse hyperbola, the transverse axis is horizontal, so the \(x\)-term comes first and is positive in the equation \( \frac{(x-h)^2}{a^2} - \frac{(y-k)^2}{b^2} = 1 \).
How do you find the asymptotes of a vertical transverse hyperbola?
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The asymptotes of a vertical transverse hyperbola centered at \((h, k)\) are given by the equations \( y = k \pm \frac{a}{b}(x - h) \), where \(a\) and \(b\) are from the hyperbola's standard form \( \frac{(y-k)^2}{a^2} - \frac{(x-h)^2}{b^2} = 1 \).
What is the relationship between \(a\), \(b\), and \(c\) in a vertical transverse hyperbola?
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In a vertical transverse hyperbola, the relationship between \(a\), \(b\), and \(c\) (the distance from the center to each focus) is \( c^2 = a^2 + b^2 \). This is used to locate the foci at \((h, k \pm c)\).